To keep things simple, assume $x^i$ are Cartesian coordinates in flat spacetime. Let's say we have a particle of mass $m$ with velocity $(v^1,v^2,v^3)$ and momentum $\gamma m (v^1,v^2,v^3)$. Now, let's focus on the component $T^{ij}$. It represents the flux of the $i$-th component of momentum through a surface of constant $x^j$. Mathematically it would be $\gamma mv^i (\text{d}x^j/\text{d}t) = \gamma mv^iv^j$. Notice that this is symmetric in $v^i$ and $v^j$ so it also represents $T^{ji}$. So we must have $T^{ij}=T^{ji}$.
Here's an explanation without math. Again, let's imagine a Newtonian particle with some momentum each in the $x$ and $y$ directions. If we double the $x$ component of momentum, the particle is now carrying $y$-momentum twice as fast in the $x$ direction. So $T^{yx}$ doubles. However at the same time it is carrying twice as much $x$-momentum in the $y$ direction. So $T^{xy}$ also doubles.
I hope this is enough to convince you that the 2 quantities are indeed equal. Including relativistic corrections into the second paragraph would just make the $x$-velocity increase by less than a factor of $2$, so the idea remains unchanged.