I was looking at a straight forward answer on internet which I am unable to find.
Can there be a strong interaction in which transformation of one quark flavour into other takes place(Eg. up quark -> down quark)?
Can there be a weak interaction in which transformation of quark flavors doesn't take place?
If both the answers are "No" then while checking a nuclear reaction/decay can't we just match quarks on both sides(by cancelling extra quark and anti quark pairs) and if same number of different quarks are present than it will be a strong interaction and it not than a weak interaction(provided other conservation laws are followed)?
If leptons are present in a nuclear reaction/decay does that necessarily means that the reaction is weak interaction(provided other conservation laws are followed)?
If photons are involved in a nuclear reaction does that means that it's a electromagnetic interaction?
A simple explanation with examples will be helpful.