I have read about conducting charged shells and spheres and know somewhat about the electric fields associated with them. But I have never found anything on non-conducting shells. I have searched online and gone through several famous physics and electrodynamics/electrostatic books. Hence I have devised a thought experiment to resolve my doubts on the topic.
Consider a charged symmetrical non-conducting shell having a charge $Q$ on its surface and $q$ at a point inside the cavity. If I try to find the electric field a point inside the cavity, I will find that they point outwards (due to $q$). But since $Q$ is already uniformly distributed on the surface, how can the field lines due to $q$ pass though the outer surface?
Another question that I have is does the uniformly distributed charge $Q$ on the surface create an electric field inside the cavity? If it does then where do the field lines due to $Q$ inside the cavity go(end)?
What would be the situation inside the cavity if instead of a non-conductor, we simply have a shell of charges and somehow managed to keep them in the situation described above?