# Circular motion of an object on the floor of equator

Object A is located on the floor at the equator.
Is that the magnitude of the normal force on A equal to its weight?

How to obtain an expression for normal reaction in terms of $$m,g,r$$ and $$\omega$$?

• – Farcher Nov 10 '20 at 14:23

The normal force from the floor (or the reading on a scale) would be N where: mg - N = mR$$ω^2$$. The, R, and, ω, are the radius and angular velocity of the earth.