Circular motion of an object on the floor of equator

Question

Object A is located on the floor at the equator.
Is that the magnitude of the normal force on A equal to its weight?

How to obtain an expression for normal reaction in terms of $m,g,r$ and $\omega$?

Answer 1

The normal force from the floor (or the reading on a scale) would be N where: mg - N = mR$ω^2$. The, R, and, ω, are the radius and angular velocity of the earth.