2
$\begingroup$

Why are the five d-orbitals denoted by the symbols $d_{z^2}, d_{x^2-y^2}, d_{xy}, d_{yz}$ and $d_{zx}$? Does it have to do with the wavefunctions of d-orbitals? The symbols for the f-orbitals are even stranger.

$\endgroup$
1

1 Answer 1

2
$\begingroup$

The names of the orbitals tell you how the wavefunction's value depends on orientation. For example, the $p$ orbitals are called $p_x$, $p_y$, and $p_z$. That means that for a $p_z$ orbital, on each sphere centered at the origin, the value of the wavefunction is proportional to $z$. So it has one positive and one negative lobe.

Similarly, the $d$ orbital $d_{xy}$ has four lobes in the $xy$ plane, two positive and two negative. The orbitals $d_{yz}$ and $d_{zx}$ are similar. The only exception to the pattern is $d_{z^2}$, which is an abbreviation of the "proper" name $d_{z^2 - x^2/2 - y^2/2}$. The same pattern continues for $f$ orbitals, again with some adjustments for the names for brevity.

If you're interested in the formalism, the sets of functions used to name $d$-orbitals form a basis for the set of traceless, rank two symmetric tensors. (That's why the name of the $d_{z^2}$ orbital has to be adjusted; the trace needs to be taken out. Tracelessness means the average value of the wavefunction on a sphere is zero.) The $f$-orbital names similarly are a basis for the set of traceless, rank three symmetric tensors.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.