0
$\begingroup$

What precisely and mathematically does it mean to have $W$ bosons carry electric charges?

We know from Wikipedia that experiments say that $W$ bosons carry electric charges: $W^\pm$ carry $+$ and $-$ of electric charges.

However, the gauge fields do not sit at any representation of the gauge group, but the gauge fields transform under the adjoint action of the gauge group. See eg https://physics.stackexchange.com/a/191982/42982.

So how can $W^\pm$ carry $+$ and $-$ of electric charges, which are charge 1 and -1 representation of $U(1)$ electromagnetic gauge group? But gauge fields do not sit at any representation of the gauge group?

Some may say, "well it is easy, we have lagrangian terms (which need to be neutral) like $$ \bar{\nu}_e W^{+ \mu} \partial_{\mu} e^-. $$ $$ \bar{\nu} W^{- \mu} \partial_{\mu} e^+. $$ So these explain why $W^\pm$ carry $+$ and $-$ of electric charges."

But again gauge fields do not sit at any representation of the gauge group (say $U(1)$?), precisely and mathematically.

$\endgroup$
6
  • $\begingroup$ What exactly do you mean by saying that the gauge fields do not sit at any representation of the gauge group but they transform under the adjoint representation? $\endgroup$ Nov 6, 2020 at 11:44
  • $\begingroup$ adjoint action - think carefully and read physics.stackexchange.com/a/191982/42982. $\endgroup$ Nov 6, 2020 at 13:26
  • $\begingroup$ The adjoint action is a representation of the group (cf. en.wikipedia.org/wiki/Adjoint_representation). The post of mine you link is about the difference between the global symmetry group $G$ and the group of gauge transformations and does not seem relevant here. I don't understand the question. $\endgroup$
    – ACuriousMind
    Nov 6, 2020 at 16:58
  • $\begingroup$ I am confused people seemed to post two answers - but they deleted it? $\endgroup$ Nov 10, 2020 at 23:57
  • $\begingroup$ Could you say more? I am confused your earlier post seems to say the other way. $\endgroup$ Dec 25, 2020 at 23:20

0

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.