# Forces on a block on an inclined plane [closed]

A block of wood rests on a plane inclined to the horizontal at an angle $$\theta$$. The smallest force acting parallel to the line of the greatest slope which will just move the block down the plane is $$F$$. If coefficient of friction is $$\mu$$, then will the weight of the block be $$W = \frac{\mu cos\theta-sin\theta}{F}$$? I've resolved this by $$Wsin\theta + F = \mu Wcos\theta$$

Your main equation $$(mg)sin\theta + F = \mu (mg) cos\theta$$ is correct.
$$mg=\frac{F}{\mu cos\theta - sin \theta}$$.