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In field theory, there's no guarantee that the energy-momentum tensor resulting from Noether's theorem is symmetric. The usual trick to construct a symmetric tensor is to add to the original energy-momentum tensor, the derivative of a function of fields that has three upper indices, and which is anti-symmetric in its first two indices, since the resulting tensor will be conserved.

My question is, although this is a guaranteed way to get a new conserved tensor, but is there a proof in the general case, that there exists at least one function of these functions that we added their derivative, that will make the new energy-momentum tensor symmetric?

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    $\begingroup$ Are you aware that the Hilbert energy-momentum tensor is guaranteed to be symmetric? $\endgroup$
    – G. Smith
    Commented Oct 16, 2020 at 20:36
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    $\begingroup$ Related: physics.stackexchange.com/q/68564/2451 , physics.stackexchange.com/q/270877/2451 and links therein. $\endgroup$
    – Qmechanic
    Commented Oct 16, 2020 at 20:40
  • $\begingroup$ @G.Smith Yes I am. However, I want the general case, and the Hilbert energy-momentum tensor is not useful with fermions, since spinor fields cause problems in this case. $\endgroup$
    – Arthur
    Commented Oct 16, 2020 at 20:59
  • $\begingroup$ @Qmechanic Thank you, it seems that the links you provided may contain what I am looking for. I will take a thorough look at them ASAP. $\endgroup$
    – Arthur
    Commented Oct 16, 2020 at 21:01

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