If we consider a spin in an external magnetic field, it starts to precess around the vector of the magnetic field. The same should be true for any angular momentum. But what does this mean for the wavefunction of the electron? To be more precise: What happens to the wavefunction if we apply an external magnetic field? Is there an easy way to picture it? If I assume a 2P3/2 state (hence L=1, s=1/2 and j=3/2) and an external magnetic field, then if we just considered this angular momentum we would see precession around B. But does this also mean that the orbital is going to precess?
If so, what would be the consequence? Would this mean that the electric dipole would also be rotating (for asymmetric orbitals) since the probability distribution would be rotating as well?
As requested, more information: I am talking about atoms. When I ask about what happens to the wavefunction, I mostly care about what any change of the wave function means for the electric dipole since the dipole moment is given by $<d>= -e <r>$. Probably one can even answer this question, when spin is completely neglected and only the evolution of $L$ in a magnetic field is considered, but I am not sure.