# How can I simulate a path for my model rocket?

Specifications:

Total weight - 1.635 N (wet).

It has a custom solid rocket motor with black powder producing 5 N for 15 sec.

So how can I calculate how high will it travel?

My rocket is guided , works on thrust vector control , i could've just flown it to find the awnsere of my question but in future , i have plans of propulsive landing so i might need to have these precise calculations.

i did some research and found out Thrust - (mass x 9.8)/mass is my acceleration , and this will apply for all the cases , also during descent?? Why doesn't the acceleration of 9.8 need to be deducted from my final acceleration?

• Hello Shitka. How much powder does the rocket store prior to ignition? Oct 2, 2020 at 4:42
• sorry , i am new to this field i did not understand what you just asked? Oct 2, 2020 at 4:44
• Your rocket weighs about 16 N, which is greater than the thrust you've provided for your motor. By these figures, your rocket shouldn't lift off the ground. Are you sure the thrust force is correct? Oct 2, 2020 at 4:49
• OK. So your question states that (when ignited) the rocket burns the black powder (or the "fuel") such that a force of 5N acts for 15 seconds. To determine its maximum height you would need to know how much of this fuel it can store. Oct 2, 2020 at 4:53
• If you're looking for a practical and accurate result and aren't as interested in learning the equations yourself, I'd recommending checking out openrocket.info Oct 2, 2020 at 4:54

So first you need to calculate the resultant force and this is $$F_R = F_{Thrust} - F_{Weight} = (5 - 1.635)N$$.
Next you should calculate the net acceleration. This would be the resultant force divided by the mass and your mass will be $$1.635/g$$. Let's call this $$a$$. Now you know that the rocket increases its velocity by $$a$$ every second so over the time interval you specify, which is 15 seconds the velocity will be $$a \times 15$$.
• That should be about right for $a=21m/s^2$. And acceleration has units of $m/s^2$ not $m/s$. Drag and aerodynamic forces are complicated and are determined by the shape of the rocket, air pressure and density. Oct 2, 2020 at 6:35