1
$\begingroup$

enter image description here

I'd like to apologies in advance for the horrible diagram, my question is regarding the following situation:

Consider a circular loop of wire placed within an external magnetic field; this field varies with time and is given by the following expression: $$\vec{B} = B_{0}f(t) \hat{k}$$ Given that the circle has a radius $r$ find an expression for the induced emf in the loop as a function of time.

My question is regarding the usage of Faraday's law, since there is a changing magnetic field, an electric current will be induced within the circle, this current however also induces its own magnetic field which opposes the change in the external field.

Most applications of Faraday's law that I have seen do not factor in this induced field with computing the total magnetic flux through the loop, in fact they neglect it. Why exactly do we neglect this induced field when computing the flux through the loop?

My Further question is that say we were trying to compute the total force on the loop as a consequence of the changing magnetic field, do we factor the induced field into such a calculation?

Improve this question
$\endgroup$

1 Answer 1

Reset to default
0
$\begingroup$

In an academic setting, the loop may be used to illustrate or test the concept of the induced emf while ignoring the effect of the induced current. In real life, the effect you cite most commonly occurs in a transformer where the current in the secondary depends on the load. As the flux from the secondary changes, the current in the primary must adjust itself to maintain the voltages and the power being drawn. As for the forces on the simple loop, I think you will find that they all lie in the plane of the loop and will give a resultant of zero.

Improve this answer
$\endgroup$
2
  • $\begingroup$ Would the loop not expand though? $\endgroup$
    – potato
    Commented Sep 29, 2020 at 22:57
  • $\begingroup$ A copper loop might expand a little bit. If the field is not uniform it can also try to translate. $\endgroup$
    – R.W. Bird
    Commented Sep 30, 2020 at 14:38

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.