0
$\begingroup$

Suppose we have a configuration like the figure below.

enter image description here

I'm asked to compute the potential $\phi (x,y) $ inside the trap.

I'm attempting this by solving the Laplace equation $\nabla^2 \phi = 0$ because there is no charge in the interior. I'm doing this change of variables:

$u= xy$ ; $v= y$

And I'm impossing this boundary conditions:

$\phi (u=1,y) = 5$ and $\phi (u=-1,y) = -5$

$\phi(u,-v)=-\phi(u,v)$

However, I'm not able to solve the resulting PDE by separation of variables.

Doing some try and error with the boundary conditions, it seems that $\phi(x,y)=5xy$ solves the problem. But that's no rigorous at all.

I want to understand a mathematical rigorous way to get this same potential. In general, I'm getting problems trying to solve Laplace equation in non spherical, cylindrical nor plane symmetry.

$\endgroup$
1
  • 1
    $\begingroup$ What is the resulting PDE, acc. you? $\endgroup$ – Gert Sep 20 '20 at 17:54

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.