Using the uncertainty relation \begin{equation} \Delta x \Delta p \geq \frac{\hbar}{2} \end{equation} we can calculate the momentum uncertainty on a length scale of a nuclei. Assuming $r_{nucleus} \sim 1 fm$ we get a momentum uncertainty of $\Delta p = 98.66 MeV \cdot c \sim 100 MeV \cdot c$.
What is the impact of this uncertainty on the kinematics of different quark types? I've read that the velocities of up and down quarks inside protons and neutrons are nearly equal to the speed of light. Now, when we get to the heavier quark types like charm or bottom, they already have rest energies of more than $1\frac{GeV}{c^2}$. Here, I would assume that they move at extremely low velocities in order to fulfill the uncertainty principle (on lenght scales of a nucleus). Are my thoughts corrrect or is there something special about quark kinematics that I have to consider here?
Sorry I'm new to this topic and it's probably a pretty simple question for you.