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Since there is a transverse Fresnel–Fizeau effect according to

Jones, R. V. (1972). "'Fresnel Aether Drag' in a Transversely Moving Medium". Proceedings of the Royal Society A. 328 (1574): 337–352. Bibcode:1972RSPSA.328..337J. doi:10.1098/rspa.1972.0081.

and

Jones, R. V. (1975). "'Aether Drag' in a Transversely Moving Medium". Proceedings of the Royal Society A. 345 (1642): 351–364. Bibcode:1975RSPSA.345..351J. doi:10.1098/rspa.1975.0141.

described for a rotating cylinder of length t as

$$ \delta = r \omega t (n - 1/n)/c $$

where $\delta$ is the transverse displacement, r radius and $\omega$ rotational speed, one could imagine that there is a rotation of the polarization plane of electromagnetic waves as they pass through a rotating medium (parallel to the rotation axis). How can this effect be determined, in terms of refractive index n and rotation $\omega$ of the rotating medium?

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2 Answers 2

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On the dragging of the plane of polarization of light propagating in a rotating medium Proc. R. Soc. London, Ser. A349, 423(1976), Author: M. A. Player

The rotation of the plane of polarization of light propagating along the axis of rotation of a rotating dielectric medium is $(1/n_ϕ) (n_g - 1/n_ϕ)$ (where $n_g$ and $n_ϕ$ are the group and phase refractive indices of the medium respectively), equal to that found for ‘aether drag’ in the transverse case.

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Another answer is

Miles Padgett, Graeme Whyte, John Girkin, Amanda Wright, Les Allen, Patrik Öhberg, and Stephen M. Barnett, "Polarization and image rotation induced by a rotating dielectric rod: an optical angular momentum interpretation," Opt. Lett. 31, 2205-2207 (2006)

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