Lorentz Transformation from Maxwell's Equations I've spent the last couple of hours trying to derive the Lorentz Transformation from Maxwell's Equations. What I ended up with is $$L_{\nu}^{-1}=\left(\begin{array}{ll}
\frac{1}{\sqrt{1-v^{2}}} & \frac{-v}{\sqrt{1-v^{2}}} \\
\frac{-v}{\sqrt{1-v^{2}}} & \frac{1}{\sqrt{1-v^{2}}}
\end{array}\right)$$
Which matches exactly with the Transformation as described in my textbook. And yet, when I search up Lorentz Transformations online, I find no matrix of the above form. What have I actually derived? Am I anywhere close to the Lorentz Transformations? Please advise.
 A: As @DanDan0101 points out in their comment to your question, if you define
$$\gamma = \frac{1}{\sqrt{1-v^2}},$$
where $v$ is the velocity measured in units of $c$ (otherwise this wouldn't make any sense dimensionally), then your matrix is just
$$L = \begin{pmatrix}\gamma & -\gamma v \\ -\gamma v & \gamma\end{pmatrix},$$
the "forward" Lorentz Transformation matrix, see this answer to What is a Lorentz boost and how to calculate it?
A: This is the Lorentz transformation for an object in a universe with one spatial dimension and a time dimension. Notice that in most texts
$$\gamma = \frac{1}{\sqrt{1-\frac{v^2}{c^2}}}$$
and it seems like in your particulat textbook the authors have opted to go with units in which the speed of light, $c=1$. Your answer is therefore correct, it's just that some authors prefer using these units to simplify calculations.
A: As @Philip points out in their answer to your question, if you define, $v=\tanh\theta$ (so that $ \gamma=\cosh\theta$), then
$$ 
L = \begin{pmatrix}\cosh\theta & -\sinh\theta \\ -\sinh\theta& \cosh\theta\end{pmatrix}
$$
which is the rapidity form of a Lorentz boost
