Since my answer was too long for a comment, I decided to post another answer on this thread answering the request "How does time affect force? I am not familiar with relativity! pls explain." asked by @Protein.
The Coloumb Force of a charge $q$ in the electric field $E$ is defined as $\frac{dp'}{dt'}=qE'$. Since time runs slower for the charge $q$ relative to the observer, the time increment $dt$ is longer by a factor of $\gamma=(1-\beta^2)^{-\frac{1}{2}}$ (Where $\beta=\frac{v}{c}$). In addition to that, the impulse $p'$ of the charge is different to the impulse $p$ measured by the observer, since mass increases with velocity. Both effects lead to the equation $\frac{d(m_{0}\gamma v)}{\gamma dt}=qE$. Deriving the impulse with the product rule ($\gamma$ is a function of $v$ and therefore also a function of time!) and then simplifying the equation results in $\gamma^2 m_{0} a=q E$. The factor $F=ma$ is the force measured by the observer and $F'=qE'$ the force measured by the moving reference frame. Substituting results in the equation
$$F=\frac{F'}{\gamma^2}$$
This means that all forces $F'$ measured by the moving reference frame are weaker by a factor of $\gamma^2$ for the observer.
We can further derive an equation for the difference of the force $F$ measured by the observer and of the force $F'$ measured by the moving reference frame:
$$\Delta F=F'-F=F'-\frac{F'}{\gamma^2}=F'(1-\frac{1}{\gamma^2})=F'(1-(1-\beta^2))=\beta^2F'$$
This apparent additional force $\Delta F$ that we measure IS in fact the repulsive magnetic force caused by the motion of the charges. This means that
$$\vec{F_{B}}=-\frac{v^2}{c^2} \vec{F_{E}}$$
where $\vec{F_{B}}$ is the force caused by the magnetic field and $\vec{F_{E}}$ is the force caused by the electric field.
This is an effect we observe in particle accelerators. When accelerating a beam of electrons to near the speed of light the attracitve magnetic force $\vec{F_{B}}$ between the electrons approaches
$$\vec{F_{B}}=\lim_{v\to c}\Bigl(-\frac{v^2}{c^2} \vec{F_{E}} \Bigr)=-\vec{F_{E}}$$
which compensates the repuslive electric force. This is pretty neat since because of that we can have pretty narrow and therefore precise electron beams or beams of different charged particles. Also notice how this effect does not only apply to electric fields, but to force fields in general!
