What mathematical approach is preferred depends primarily on the Biot number $\text{Bi}$ of the system:
$$\text{Bi}=\frac{hR}{k}$$
where $h$ is the convective heat transfer coefficient, $k$ the thermal conductivity of the sphere's material and $R$ the sphere's radius.
- High $\text{Bi}$ number:
This means the heat loss proceeds primarily by convection and that temperature gradients inside the sphere are small:
$$\frac{\partial T}{\partial r} \approx 0$$
It also means that lumped thermal analysis can be applied here. We can use Newton's Law of Cooling:
$$-mc_p\frac{\text{d}T(t)}{\text{d}t}=hA[T(t)-T_e]\tag{1}$$
with $T_e$ the environment's temperature (far away from the sphere's surface)
$(1)$ is an ODE with separation of vaiables and is easy to solve.
- Low $\text{Bi}$ number:
Here conduction prevails over convection and significant temperature gradients inside the sphere exist:
$$\frac{\partial T}{\partial r} < 0$$
Lumped thermal analysis is likely to cause significant error here and we need to use Fourier's Heat Equation.
Define $u(r,t)=T(r,t)-T_e$, so that with Fourier for a sphere:
$$\frac{\partial u}{\partial t}=\frac{\alpha}{r^2}\frac{\partial}{\partial r}\Big(r^2\frac{\partial u}{\partial r}\Big)$$
Make a subsitution:
$$v(r,t)=u(r,t)r$$
We obtain:
$$v_t=\alpha v_{rr}\tag{1}$$
BCs:
$$v_r(0,t)=0$$
BC from convection:
$$-ku_r(R,t)=hu(R,t)$$
Transcribed:
$$-kv_r(R,t)=\Big(h-\frac{k}{R}\Big)v(R,t)\tag{2}$$
Initial condition:
$$v(r,0)=(T_0-T_e)r$$
Going back to $(1)$:
$$v_t=\alpha v_{rr}\tag{1}$$
Using Ansatz and separation:
$$v(x,t)=R(r)\Theta(t)$$
allow determining $v(r)$ and thus $u(r)$.