# On a fixed beam, which force induces a counterclockwise torque

Given this situation ($$P$$ is the point where the beam is fixed), which force induces a torque that is counterclockwise?

I want to use that : $$\boldsymbol{\tau} = \textbf{r} \times \textbf{F}$$ , however what does counter clockwise torque mean? Intuitionally it would seem that $$F_2$$ would turn the beam around its own axis (counter clockwise) but so would $$F_3$$ and $$F_5$$.

So my question actually is: what does counter clockwise torque mean in the context of this exercise?

Any hints are greatly appreciated.