# Pressure Variations in an Atomizer

This question has been asked two times

Now my question will be different from all those questions, since I will be asking where exactly I am having trouble understanding the working of an atomizer rather than just asking explain the working of atomizer.

While deriving equation of efflux , we take the pressure of liquid to be at the atmospheric pressure i.e $$P_2= P_o$$

Now when I am applying this logic to an atomizer, I am getting a contradiction :

Now the liquid at the horizontal level below the height is at $$P_o$$ . Since pressure increases with depth

$$P_o>P_1$$.

When we look at the horizontal tube in order to liquid to flow $$P_3>P_1>\mathbf P_o$$ . Now this leads to an absurd result as earlier i have shown $$P_o>P_1$$ but here $$P_1>P_0$$

Why the pressure end of horizontal tube is $$P_o$$?

As it was how we derived it in equation efflux.

My question

Why the pressure at the end of horizontal tube is not $$P_0$$? I am assuming that assuming that me taking pressure $$P_o$$ at the end of the horizontal tube is my only mistake . If there is any other mistake please point out freely.

What am I missing here ?

The fact that $$P_3>P_1>P_o$$ is not true.
The velocity of the liquid decreases from going to $$P_1 to P_0$$ . The pressure difference is not enough to stop the liquid from flowing out the tube.