This question has been asked two times

  1. Similar question 1
  2. Similar question 2

Now my question will be different from all those questions, since I will be asking where exactly I am having trouble understanding the working of an atomizer rather than just asking explain the working of atomizer.

While deriving equation of efflux , we take the pressure of liquid to be at the atmospheric pressure i.e $P_2= P_o$

Now when I am applying this logic to an atomizer, I am getting a contradiction :


Now the liquid at the horizontal level below the height is at $P_o$ . Since pressure increases with depth


When we look at the horizontal tube in order to liquid to flow $P_3>P_1>\mathbf P_o$ . Now this leads to an absurd result as earlier i have shown $P_o>P_1$ but here $P_1>P_0$

Why the pressure end of horizontal tube is $P_o$?

As it was how we derived it in equation efflux.

My question

Why the pressure at the end of horizontal tube is not $P_0$? I am assuming that assuming that me taking pressure $P_o$ at the end of the horizontal tube is my only mistake . If there is any other mistake please point out freely.

What am I missing here ?


1 Answer 1


The fact that $P_3>P_1>P_o$ is not true.

The velocity of the liquid decreases from going to $P_1 to P_0$ . The pressure difference is not enough to stop the liquid from flowing out the tube.


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.