# Flow rate and extrusion speed of a syringe

I want to calculate the flow rate of a liquid (very high viscosity, but we can assume laminar flow, for now, so I get an idea of how to go about this problem) I understand that I have to use Poiseuille's equation to calculate the flow rate along a tube length, L. A good example is already in this answer: link

However, the syringe I need to model has a long straight metal nozzle after the barrel, so I need to account for the flow area changes.

I know the applied pressure is 250 kPa in the barrel. Could I use the equation:

Flowrate = [πr4(P−P0)]/8ηl

to calculate the flow rate in the barrel, then use the equation:

V1A1 = V2A2

to calculate the new flow rate in the nozzle?

However, should the P0 term in P−P0 be different from [applied pressure - atm pressure] between the interface of the barrel and the nozzle?

I understand it that there should be 3 different Ps in the system. P2 at the interface between the piston and the top of the barrel when it meets the liquid, P1 at the interface between the bottom of the barrel and the top of the nozzle where the flow area changes, and P0 at the end of the nozzle which is atmospheric pressure.

I am a little stuck because I don't know how to find P2 if that is the case...

• Typically, the pressure drop in the syringe is going to totally dominate. So, in practice, you can neglect the pressure drop from the barrel and the constriction. Commented Jul 28, 2020 at 2:15
• Bernoulli doesn't apply for high viscosity flow. Commented Apr 25, 2022 at 14:28

In the case of a pipe where sudden contractions (or expansions), regulating valves, bends etc occur, Bernoulli's Equation (here for negligible gravity) is written as:

$$p_1+\frac12 \rho v_1^2=p_2+\frac12 \rho v_2^2+\Delta E$$

Where:

$$\Delta E=\Delta\Big(p+\frac12 \rho v^2\Big)$$

For sudden contractions ('vena contracta'), the coefficient of contraction is:

$$\mu=\frac{A_3}{A_2}$$

It can then be derived (see link above) that:

$$\Delta E=\frac12 \rho \Big(\frac{1}{\mu}-1\Big)^2\Big(\frac{A_1}{A_2}\Big)v_1^2$$

And empirically:

$$\mu=0.63+0.37\Big(\frac{A_2}{A_1}\Big)^3$$

You may want to apply mass and momentum conservation equations to find the mass flow rate at a given section.

If fluid and flow are incompressible, $$\rho A_i v_i = const$$ and $$p_i + \frac{1}{2}\rho v_i ^2 = const$$ are the laws you are looking for, given that your $$L$$ keeps gravitation potential negligible.

• This doesn't answer the question at all.
– Gert
Commented Jul 27, 2020 at 16:24