3
$\begingroup$

Are degenerate states stationary in quantum mechanics? I know that stationary state means single wavefunction corresponding to single energy. But, what will be in the case of several wavefunctions corresponds to single energy (e.g. degenerate states). are All of them stationary in that case? Can you pls give me explicit difference of stationary state and non stationary?

$\endgroup$
2
$\begingroup$

The state is called stationary if it is an eigenstate of the Hamiltonian.

Degeneracy is a property of the spectrum of an operator. An eigenvalue is called degenerate if there are at least two linearly independent eigenstates with the same eigenvalue.

Also, when you hear the term degenerate without specifying which operator it applies to, usually it is assumed that this operator is the Hamiltonian.

So yes, degenerate states of the Hamiltonian are by definition stationary, and they have the same energy.

$\endgroup$
3
  • $\begingroup$ what if hamiltonian contains time dependent potential? $\endgroup$ Jul 26 '20 at 6:16
  • $\begingroup$ @AltuhaAbdu: Just think of the Stern-Gerlach experiment: What we found there is that by changing the Hamiltonian "quickly" the systems wave function can not adapt. Therefore, it is projected/decomposed onto the new eigenbasis. $\endgroup$
    – Semoi
    Jul 26 '20 at 6:43
  • $\begingroup$ @AltuhaAbdu if the Hamiltonian changes with time, the eigenstate of $H(t_1)$ are not eigenstates of $H(t_2)$. Also, the eigenvalues change, too. There is no energy conservation. $\endgroup$ Jul 26 '20 at 10:31

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.