I would like to know how many satellites are physically able to be in place, at the same time, orbiting the earth. Lets ignore which Nations need or use the most satellites (area in space above them) and assume an even distribution. My understanding is each satellite is inline with a degree on earth (longitude), but there are only 180 of these. Would you then be able to line up satellites on each degree of latitude for each degree of longitude? So 180 x 180 = 32400? Or is there more to this? Could you put a satellite either further or nearer to the earth so they would almost overlap to make room for more?

  • $\begingroup$ Why do you think that a satellite always takes up one degree? Have you considered that the solid angle depends on the radius of the orbit. You could have multiple satellites above each other on the same path (projected on the eath's surface) $\endgroup$
    – luksen
    Commented Mar 12, 2013 at 13:15
  • $\begingroup$ @luksen I dont think it takes up a degree, I thought I saw somewhere that they are positioned on a degree. So I guess you could have as many satellites as you want provided you're not bothered about all the shade down here $\endgroup$ Commented Mar 12, 2013 at 13:22
  • $\begingroup$ It's not true that all satellites have integer latitude and longitude. See this list of satellites in geosynchronous orbit $\endgroup$ Commented Aug 31, 2016 at 3:07

2 Answers 2


This is actually quite a complex problem. At large numbers of satellites, gravitational effects need to be considered. A real answer would need values such as 'every satellite has the same mass and volume' etc. Basically you can keep adding satellites until Earth becomes a black hole. Satellites are very dense since they have lots of metal (which is a dense material) In my opinion, a great 'answer' to this question would be a fun computer simulation.

If we just use the values given by Phil H, we fit in satellites between 2000 km and 35786 km altitudes. $R_E$, the radius of the Earth is 6371km. So we calculate the volume: $V_{total}=\frac{4}{3} \pi [(d_2+R_E)^3-(d_1+R_E)^3]=\frac{4}{3}\pi (42157^3-8371^3)=9.341\times10^{14}\,\text{km}^3$

We assume that all the satellites have mass of $m_s = 800\,\text{kg}$ (note that this is a 'fantasy' problem so we don't really need to follow real world statistics) and volume $V_s=4.8 \,\text{m} \times 4.8 \,\text{m} \times 5.5 \,\text{m} = 1.267 \times 10^{-7} \, \text{km}^3$

Thus, the total mass of the orbiting satellites will be $M_{total} = \frac{m_s}{V_s} V_{total}= 5.90 \times 10^{24}\,\text{kg}$

Now let's compare that to the mass of the Earth, $M_E=5.97\times 10^{24} \,\text{kg}$.

Notice how $M_{total} \approx M_E$, though this is just due to some values which we chose and does not arise from some values which arise from nature.


Satellites are very small, so there would have to be an enormous number to use up the 'space' available.

You mention lattitude and longitude which suggests an explanation of LEO and GEO (Low and Geostationary Earth Orbits) would help. in Geostationary orbit (e.g. TV satellites), the satellite orbits at a specific distance so that it's always in the same place in the sky, as its orbit is then 24 hours long. This special orbit runs around the equator, as any other inclination would make it move in the sky, in a figure of eight.

In a lower orbit, the satellite appears over the horizon, zips across the sky and disappears again. This is why GPS systems don't have an antenna or dish that you point at one place, as GPS uses a constellation (group) of many satellites at 20,200 km altitude.

So the available space for satellites extends from Low Earth Orbit (2,000 km up), e.g. telecomms satellites and Hubble, out to the moon, which is our only natural satellite. Mostly they stay between LEO and GEO (35,786 km altitude).

Having said all that, the more we put up there, the more junk we end up with as pieces fall off satellites, or they collide, or they are hit by other space junk. This is increasingly a concern as early missions largely assumed everything would end up burning up in the atmosphere eventually.

The space available for satellites, then, is very large. Even in a single LEO orbit there is more 'space' than the distance around the equator. The Geostationary orbit has a limited number of spaces available by international agreement to prevent collisions or interference.

  • $\begingroup$ So all the satellites are running around the equator? Or just the GEO, TV satellites? $\endgroup$ Commented Mar 12, 2013 at 13:26
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    $\begingroup$ The GEO satellites are running around the equator, and so are some of the other satellites. Most non-GEO satellites, however, have a different inclination, because the geostationary bit is the main reason to put a satellite above the equator. At low orbital altitudes, the satellite is visible for a smaller area of the Earth's surface, so to reach the majority of users in the northern hemisphere (North America, Europe) they have to have a higher inclination to be any use. These satellites are then less useful for much of their orbit. $\endgroup$
    – Phil H
    Commented Mar 12, 2013 at 13:43

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