# Is the work done by gravity equal to the work done against friction?

If there is a block on a ramp, and it slides to the bottom (with friction), then is the work done by gravity always equal to the work done against friction?

• Do you mean "work done by friction"? Forces do work. What does "work done against friction" mean? Jul 15, 2020 at 15:00
• Since the displacement is opposite the force, wouldn't it be considered work done against friction? Jul 15, 2020 at 15:03
• I think the usual way to describe it is "the work done by friction is negative". The phrase "work done against friction" makes it sound like you are focusing on other things doing the work, but here you really do mean "the work done by friction". It is much less confusing to say "work done by the force" in all cases. Jul 15, 2020 at 15:05
• @BioPhysicist, It is usual to talk of work done against friction. It is already clear that the work is done by gravity, and we are simply dividing it into parts, as described by Dale. The idea of work being done by friction, whether positive or negative, is bizarre, because friction does not cause movement (only opposes it), so friction cannot do work. Jul 15, 2020 at 21:52
• @CharlesFrancis The work done by a force $\mathbf F$ is $\int\mathbf F\cdot\text d\mathbf x$, so both gravity and friction do work here. Unless you are saying $\int\mathbf F\cdot\text d\mathbf x=0$ here for friction? What about an object sliding on a flat surface and coming to rest due to friction. You would say there is no force doing work here? What is doing the "work against friction" in that scenario? Just because work is negative doesn't mean it is nonexistent or there is work "against" it. Jul 15, 2020 at 22:17

• Technically $W_\text{grav}+W_\text{fric}=\Delta K$, not $W_\text{grav}=W_\text{fric}+\Delta K$ Jul 15, 2020 at 14:56
• @Julia $W_\text{grav}=-\Delta U_\text{grav}$, which is true for all conservative forces Jul 15, 2020 at 15:10