# Current flow in parallel capacitors connected with their polarities reversed

If you take two capacitors, one with capacitance C and the other with 2C, and charge them to voltages V and 2V volts, assuming CV = Q, they'd have charges Q and 4Q.

Now when these two are connected in parallel with oppositely charged plates connected, charge flow takes place till terminal potentials are equal. I assumed it'd be something like this:

It seems like the electron density on the negatively charged plate(which I've shaded according to charge intensity) decreases as charge flows to the positive plate(This takes place from both of the negative plates; I've only shown one.). Eventually, it'll be enough to flip the polarity of the capacitor with the smaller charge, and bring down the charge on the other one so that the voltages end up equal.

It seems as though this doesn't check out, though. What am I missing here?

Edit: I've got to find the final energy of the configuration; it's actually $$\frac{3CV^2}{2}$$, but I'm always getting $$\frac{5CV^2}{6}$$.

• Can you elaborate more on why your answer doesn't "check out"? It's unclear what your question really is. Jul 8, 2020 at 12:46
• Info added, but I just wanted to know if that was the way it worked. Jul 8, 2020 at 13:44