# What does the adjoint of a QFT Dirac plane-wave spinor represent, physically?

So, using the Dirac spinor notation for plane-wave electrons and positrons from HERE, and the definition of the adjoint of $$\psi$$ = $$\psi^{*T} \gamma^0$$, and applying that to the "up" electron (with the Dirac version of $$\gamma^0$$), I get

$$\bar{\psi} = e^{ip\cdot x} [ 1 \space 0 \space -p_z/(E+m) \space \space (-p_x+ip_y)/(E+m)]$$

The vector part is the same as the original electron's vector, with $$p_x$$ and $$p_z$$ reversed, but not $$p_y$$. In addition, the exponent term now represents "negative energy", or an anti-particle. But the momentum term's positions in the vector are for those of a particle.

How is this to be interpreted physically? In other words, what kind of particle (if any) does it represent?