Isn't the disturbance in quantum field an interpretation of quantum wave function? In quantum mechanics, a particle is neither a wave nor a particle but is described by a wave function which does not have a physical interpretation. But in quantum field theory, a particle is a disturbance in the associated field. Isn't the disturbance in quantum field an interpretation of quantum wave function?
 A: 
In quantum mechanics, a particle is neither a wave nor a particle but is described by a wave function which does not have a physical interpretation

Note the bold a particle. The quantum mechanical equations , Dirac, Klein Gordon, quantized Maxwell, all describe a single particle.
The postulates of Quantum Field Theory are the postulates of Quantum mechanics, exactly. QFT was invented as a mathematical tool for the study of many particle systems in quantum mechanics, that allows for calculating crossections of interactions and decay probabilities.

Isn't the disturbance in quantum field an interpretation of quantum wave function?

If you mean by interpretation a different mathematical formulation of the wave function for interacting particles, the answer is yes.
Note that the fields on which the creation and annihilation operators work are the plane wave wavefunctions, (for example see here) i.e. the solution of the corresponding quantum mechanical equations for single particles. As a probability the $Ψ^*Ψ$ of a plane wave cannot describe the location of a particle as measured in the lab. For single tracks of particles the wavepacket solution has to be used .
For calculating crossections and decays, the Feynman diagrams using QFT are accurate  and validated by experiments.
See also my answer here .
