# Electroweak scalar triplet coupled to Higgs

Suppose we add to the SM the following electroweak scalar triplet with hypercharge $$Y_T=-1$$ $$T=\begin{pmatrix} t^0 & t^-/\sqrt{2} \\ t^-\sqrt{2} & t^{--} \end{pmatrix}$$

where the superscript indicates the electric charge of each component field. It couples to the Higgs $$H$$ with the following Lagrangian: $$L_T= tr|D_\mu T|^2-m^2_Ttr|T|^2 + \Lambda TH^2 + \Lambda(TH^2)^*$$ where $$m_t$$, $$\Lambda$$ are new mass parameters and $$D_\mu T= (\partial_\mu T-igW^a_\mu\frac{\sigma^a}{2}T-igTW^a_\mu\frac{\sigma^a}{2}-ig'Y_TB_\mu T$$ $$TH^2\equiv T_{ab}\epsilon^{ac}\epsilon^{bd}H_cH_d \, .$$

Considering the usual Higgs potential $$V(H)=-m^2|H|^2-\lambda(H^\dagger H)^2$$

we want:

1. Find the minimum of the full potential, the bound on the triplet vev and the constraints on the $$m^2_T /\Lambda$$ ratio
2. Gauge bosons mass spectrum

1. For what concern the full potential, it's clear that the $$\Lambda$$ coupling breaks the $$SO(3)$$ custodial symmetry. In fact, using only the neutral component of T and opening the Higgs we have:

$$V=m^2_T(t^0)^2-\Lambda\frac{t^0}{2}(\phi_{1b}^2-\phi_{2b}^2+2i\phi_{1b}\phi_{2b})-\Lambda\frac{t^0}{2}(\phi_{1b}^2-\phi_{2b}^2-2i\phi_{1b}\phi_{2b})-\frac{m^2}{2}(\phi_{1a}^2+\phi_{2a}^2+\phi_{1b}^2+\phi_{2b}^2)+\lambda(\phi_{1a}^2+\phi_{2a}^2+\phi_{1b}^2+\phi_{2b}^2)$$

so, I would say that $$\Delta\rho\sim\Lambda/v$$. Performing the first derivative I find:

$$\begin{equation} V_T=2m^2_TTr[T_{ab}]-\Lambda\epsilon^{ac}\epsilon^{bd}H_cH_d=0\end{equation}$$

$$\begin{equation} V_H=-2\Lambda T_{ab}\epsilon^{ac}\epsilon^{bd}-m^2H^\dagger_c+2\lambda|H|^2H^\dagger_c=0. \end{equation}$$

Now I have a doubt: for the vev of the triplet T, I can choose whatever "gauge" I want or is there a more privileged choice? I would say that, according to CP invariance, only an em neutral component can acquire a vev, so i would let $$t^0$$ acquires a vev: $$=v_0\delta_{a1}\delta_{b1} \, .$$
So I'm not sure if this choice should be an input in the eqs. and see if it minimizes the potential or rather an output. Anyway, substituting that in the first eq. I find the condition for the Higgs vev (could be seen as a consistency check of my choice?): $$V_T=2m^2_Tv_0-\Lambda ()^2=0$$ which, denoting $$v$$ the Higgs vev, implies: $$\frac{m^2_T}{\Lambda}=\frac{v^2}{v_0} \, .$$

1. After the usual manipulations for the kinetic term of $$T$$ in the unitary gauge, I find:

$$L_{mass}=\frac{v_0^2}{4}\biggl[\bigl(gW_\mu^3-2g'B\mu)^2+g^2W_\mu^+W_\mu^-\biggr]$$ doubt: I haven't done any calculation yet, but how is it possible to find a mass term for the $$Z$$ if I have already a precise constraint (the one from Higgs sector) for the $$(B,W^3)$$ rotation into $$(A,Z)$$?