# What is the role of center-tapping in a full wave rectifier?

Note: I have already tried googling. Although similar questions have been asked on different forums, I couldn't find a detailed explanation, which I could really understand. Circuit diagram courtesy of Wikipedia.

This is very easy to understand why centeraltap transformer is needed in a full wave rectifier. Let us assume that we have a simple transformer, and there are two diodes and the central wire coming out from the transformer is not present there which is obvious since we are not using centeraltap transformer. So now see the figure In first case let A be at lower potential i.e. negative and B be at higher potential i.e. positive. So due to induction 1 will become positive and 2 will become negative. Now since 1 is at higher potential so D1 will be forward biased and current will flow through it but since 2 is at lower potential D2 will be reversed biased and no current will flow through it so the circuit will not work because in one case D2 will be reverse biased and in other D1 will be reverse biased. Now if we take a centeraltap trnsformer as shown in figure there will be following sign convention in case 1 and just opposite in case 2. So in case 1 as you can see D1 is forward biased so current will flow through D1 and R and will go to the central low potential point and the circuit will be completed for case 1 and in case 2 the current will flow through D2 and R and again will go to the centeral low potential point and the circuit will again be completed and it will rectifier the full wave that is it's negative as well as positive half cycle in a positive variable DC current. So that is the reason a center tap transformer is used in a full wave rectifier because you need to rectify full wave. Hope it helped you.

• Can you explain how can 1 become positive due to induction? What do you mean by induction here? I can't grasp the concept. – Samama Fahim Mar 19 '13 at 13:07
• induction is the process of charging an uncharged body by bringing it close to a charged body. When you bring a positively charged sphere near to an uncharged sphere the uncharged sphere gets a negative charge on its one side due to the attraction of the positive charge on the another sphere see the image below in the answer – Dimensionless Mar 19 '13 at 13:15
• According to figure of simple transformer above, If we connect only one diode with a simple transformer, then during the positive half cycle of AC, the diode will be reverse-biased as due to induction 1 will become negative, and in the negative half cycle 1 will become positive due to induction and the diode will be forward biased. Does this happen if the condition is so? – Samama Fahim Mar 19 '13 at 13:34
• yes it is it's working principal – Dimensionless Mar 19 '13 at 14:59
• hey Manishearth I have already answered the question it was for the comment I posted it so that he could understand – Dimensionless Mar 19 '13 at 18:47