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The wave function (this is the wave function in mechanical waves. It is not the wave equation, which is derived from this wave function. Neither is this the wave function for quantum mechanics!) is given as: \begin{align} y(x,t)&=A\cos(kx \pm \omega t + \phi) \end{align} (where $k$ is the wavenumber, $x$ is the position, $A$ is the amplitude, $\omega$ is the angular frequency, $t$ is the time, and $\phi$ is the phase difference)

From my knowledge, the $\pm$ in front of $\omega t$ is to account for wave direction. However, mathematically, I am unable to intuitively understand or even picture why this $\pm$ sign in front of $\omega t$ (which accounts for the time dependency of the wave function) should account for direction. Hence, may I know the connection between this $\pm$ sign and the direction of the wave propagation? Thank you!

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  • $\begingroup$ Hint: Solve for the positions of crests and troughs in an $(x,t)$ diagram. $\endgroup$
    – Qmechanic
    Commented May 22, 2020 at 11:06
  • $\begingroup$ To clarify, I should calculate the number of crests and troughs? Or should I solve for something else, if so, what exactly? $\endgroup$
    – Lucas Tan
    Commented May 22, 2020 at 11:13
  • $\begingroup$ @LucasTan you should calculate positions of the crests and how these positions depend on time. $\endgroup$
    – Ruslan
    Commented May 22, 2020 at 11:48
  • $\begingroup$ That isn't the wave function. That is just a possible solution to the wave equation. $\endgroup$ Commented May 22, 2020 at 11:58
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    $\begingroup$ Does this answer your question? How to determine the direction of a wave propagation? $\endgroup$ Commented May 22, 2020 at 11:59

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