Now since only two electrons (or any quantum object) can be maximally entangled due to the monogamy of entanglement how does the general $n$-qubit states which has more than two qubits make use of entangled states to increase the computational space to $2^n$? so for example take this three qubit general state
$$a1|000⟩+a2|001⟩+a3|010⟩+a4|100⟩+a5|110⟩+a6|101⟩+a7|111⟩+a8|011⟩$$
If only 2 qubits out of these 3 are entangled how can we represent it in such a form?
same question for any $n$-qubit general state
$$∣ψ⟩_{n-qubit}= a1∣000…000⟩+ a2∣000…001⟩+a3 ∣000…010⟩+⋯.$$
i always understood general states as that all possible bits e:g l000>, l001>, ... (for example these three bits) cannot be computed independently since they are entangled but now that i know that only two can be maximally entangled how can we add a third non entangled qubit in that relation?. what part am i missing?