# Does Acceleration due to Gravity take into consideration the centrifugal acceleration due to Earth's spin?

Is the gravitational acceleration we consider only the attraction due to the Earth's gravity or is it that of gravity plus the attraction due to Earth spinning?

We know that earth produces an acceleration towards the centre on any body near it due to gravitational attraction.

We denote this acceleration as $$g$$.

But we also know that any body on Earth is also undergoing rotational motion due to earth's Spin. So every body should experience an outward centrifugal acceleration.

Does acceleration due to gravity $$g$$ take the centrifugal acceleration into consideration?

• I didn't understand what do you mean by $\textit{"attraction of earth's gravity"}$. However, we consider $g$ only due to interaction between earth and body. – SarGe May 14 at 4:18
• Have you calculated whether it makes much difference? – G. Smith May 14 at 4:23
• The centrifugal pseudoforce acts outward, not inward. – Sandejo May 14 at 5:53

$$g$$ is measured by observing the freefall acceleration of objects in a vacuum. Since this is taking place in the non-inertial, rotating reference frame of the Earth's surface, it does include the centrifugal effects on acceleration. However, it is also worth noting that this effect is generally not very large: $$g\approx 9.8 \ \mathrm{m/s^2}$$ across the Earth, while at the equator (where centrifugal acceleration is greatest) the centrifugal acceleration is given by $$a_c=\left( \frac{2\pi}{1 \mathrm{day}} \right)^2 R_{\oplus,\mathrm{eq}} = 0.0337 \ \mathrm{m/s^2}$$, where $$R_\oplus$$ is the equatorial radius of the earth.
• FWIW, Google Calculator can easily do this: (radius of earth)*(2*pi/(1 day))^2 – PM 2Ring Nov 22 at 6:04