0
$\begingroup$

We use time independent schrodinger equation to find Stationary state solution for some potentials. My question is that, these Stationary state solutions are physically reliable or not? I am asking this because these solutions provide us state of definite energy i.e, we can measure energy with zero uncertainty. But physically there must be some non-zero uncertainty associated with them.

$\endgroup$
  • $\begingroup$ Why do you say that there must be non-zero uncertainty? $\endgroup$ – Superfast Jellyfish May 13 at 16:56
  • $\begingroup$ @SuperfastJellyfish Because of energy time uncertainty relation. $\endgroup$ – Harsh Nigam May 13 at 18:17
1
$\begingroup$

There are many kinds of physical uncertainties, not all of them (directly) related to quantum mechanics. To name just a few:

  • the fundamental quantum uncertainty
  • the uncertainty due to the fact that our model only approximates the essential elements of the system that we study
  • the uncertainty due to some objective limitations, like impossibility to write down and solve the equations for all the particles in the system (the subject of statistical physics), the fact that energy measurements done withing finite time, etc.
  • Finally, there are uncertainties due to the limitations of the existing equipment (like the biggest available particle accelerator)

The fundamental difference between quantum mechanics and classical mechanics is in treating the first type of uncertainty. Where in classical mechanics measurements are theoretically possible with infinite precision (assuming that we have overcome other uncertainties), in quantum mechanics this is possible only in some situations. Stationary state is such a situation. This does not prevent other uncertainties from disturbing our measurements:

  • the interactions mean that the actual energy is not the one that we calculated and that the stationary state decays
  • the finite measurement time means that we are limited by the Heisenberg uncertainty principle ($\Delta E\Delta t \geq \hbar/2$).
  • the imperfect equipment adds additional error bars
| cite | improve this answer | |
$\endgroup$
  • $\begingroup$ My question is particularly about quantum uncertainty (energy and time uncertainty).Heisenberg principle says that if energy uncertainty is zero then Mean lifetime will be infinite.But this doesn't really happens,right!? $\endgroup$ – Harsh Nigam May 13 at 18:17
  • $\begingroup$ Indeed, it doesn't happen, because the energy and time di nit commute, so you will have uncertainty of measurement $\hbar/(2\Delta t)$, where $\Delta t$ is the time of measurement, which is definitely shorter than the age of the universe, human lifetime, etc. $\endgroup$ – Vadim May 13 at 19:11

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.