# Gauss law - charge inside a conductor

If there is a point charge inside a shell conductor for example, making a Gaussian surface around the point charge will tell me there is a non-zero flux, meaning non-zero electric field inside, but how is that possible if electric field inside any conductor is zero because charges on the inner surface redistribute to cancel the electric field?

• But that point charge is in the cavity, so what's the problem in having an electric field inside the cavity?
– user258881
Commented May 9, 2020 at 5:29

Metals have access to a sea of free electrons. Under equilibrium condition the net movement of the electrons inside the metal is zero. And this is reflected in the fact that metals have no field inside them.

• Simple answer- Because it can not. There is no reason why it would be able to do so. For every arbitrary gaussian surface you draw inside the cavity, the net charge inside would be $q$ since there can be no inductions in free space. So, since $$\displaystyle \int \textbf{E}.\textbf{ds} \neq 0$$ for any arbitrary surface, electric field has to be non zero any way. Commented May 10, 2020 at 3:42