In uniform circular motion, for my lab, I used the formula $𝐹_𝑐=4\pi^2 m r \times$(𝑓2) to find the experimental centripetal force

and I use $F_{cp}= 4\pi^2mr$ to find the theoretical value of $F_c$. I ended up with the same value of $F_c$.

I concluded that frequency does not affect that much the centripetal force but I do not have enough arguments. can I get help on this please?

  • 1
    $\begingroup$ Please use Latex to format your formulas. Also, what kind of system are you looking at and what is $f_2$? What is your exact question? With the information given it's almost impossible to give an answer. $\endgroup$
    – Sito
    Apr 30, 2020 at 23:28
  • $\begingroup$ the theoretical formula does not generally looks like that; it is $F=m\omega^2r$... And your "experimental" centripetal force formula is just a duplicate of the theoretical one, as $2\pi f$ is just $\omega$. $\endgroup$ May 1, 2020 at 1:18
  • $\begingroup$ What is (f2)? Also, the unit of mass x length is not force (your 2nd equation). Are there terms missing in your question? $\endgroup$
    – Bill N
    May 1, 2020 at 1:25
  • $\begingroup$ $F_{cp}= 4\pi^2mr$ try to apply basic dimensional analysis and you should see some issues. $\endgroup$ May 1, 2020 at 3:16

1 Answer 1


The centripetal force acting on a body of mass $m$ in uniform circular motion located at a distance $r$ from the axis of rotation is: $$F_{c} = m\omega^2 r = m(2\pi f)^2 r = 4\pi^2 f^2 m r$$

Here, $\omega$ is the angular frequency of rotation and $f$ is the number of rotations per second.

The only way you arrived at your conclusion is because $f=1$. Coming to such a conclusion that the frequency does not affect the centripetal force that much is highly erroneous as it is apparent from the relation that the centripetal force varies as frequency squared.


Not the answer you're looking for? Browse other questions tagged or ask your own question.