# Equilibrium position of a spring vs its mean position

“Equilibrium position of a massless spring vs its mean position”

I am confused about these two terms. Do they mean the same thing? I understand the term ‘mean position’. Let’s say one end of a vertical massless spring is attached to the ceiling and the other end is attached to a mass m. When the mass is released, the spring stretches and at one point, mg equals the spring force kx. And that’s the mean position, at x = $$\frac{mg}{k}$$

Is equilibrium position just another term for mean position? And since mean position equals $$\frac{mg}{k}$$, can I say that mean position of a spring is different for different masses?