It is well known that Madelung formulation is alternative to the Schrödinger Formulation, cf. this previous Madelung transformation Phys.SE post. I wanted to know what makes Schrödinger's formulation superior to that of Madelung, and in particular, when does the Madelung formulation fail?
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1$\begingroup$ And why do you think there are some superiority? I think they have same relation to Schrodinger as Euler equations to Newtons one. $\endgroup$– m0nhawkFeb 15, 2013 at 10:44
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1 Answer
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This is a translation from the German Wikipedia entry about the Madelung equations:
Due to their non-linearity, the Madelung-equations are difficult to use in practise. However, they show that there exist non-linear equations that are based on linear equations.
Hope this helps.
