Partition function for quantum Ising model I have hamiltonian for fermionic field as
$${\cal H}_F=E_0+\int dx[\frac{v}{2}(\Psi^\dagger\frac{\partial \Psi^\dagger}{\partial x}-\Psi\frac{\partial \Psi}{\partial x})+\Delta\Psi^\dagger\Psi]\tag{1}$$
And partition function is
$$\mathcal{Z}=Tre^{-\frac{H_F}{T}}=\int D\Psi D\Psi^{\dagger}e^{-\int_0^{1/T}dx^0 dx^1\mathcal{L}}. \tag{2}$$ 
And
$$\mathcal{L}=\frac{-\dot\iota}{2}\Big(\Psi^\dagger\frac{\partial\Psi}{\partial x^0}+\Psi\frac{\partial\Psi^\dagger}{\partial x^0}+\Psi^\dagger\frac{\partial\Psi^\dagger}{\partial x^1}-\Psi\frac{\partial\Psi}{\partial x^1}\Big)$$
The text says, by using Grassmann variables, one can write the partition function given above. I read about Grassmann variable (Grassmann Algebra), but still, I don't know how to write the partition function given above.
We get Hamiltonian above after Jordan-Winger and Bogoliubov transformation of the quantum Ising model in a transverse field.
Text also talks about Majorana fermions. How to relate above field as Majorana field fermion?
 A: As you can see the action is a sesquilinear form in $\Phi, \Phi^\dagger$. This means that you can write
$$
S = \Phi^\dagger G \Phi.
$$
Now you realize that the partition function is a gaussian (infinite dimensional) integral over Grassmann variables, i.e.
$$
Z = \int D\Phi D\Phi^\dagger e^{- \Phi^\dagger G \Phi }.
$$
The formula for Gaussian integral over Grassmann variables is similar to the one for complex variables with an additional (-1). 
The formula reads
$$
Z = \det(G).
$$
The problem is reduced to the computation of that (infinite dimensional) determinant.
Note
In the post there is some confusion about naming the fields $\Phi$ vs $\Psi$. Also the Hamiltonian has a mass term $\Delta$ which is absent in the Lagrangian.
Edit 04/06/2020
I overlooked one important detail. The Hamiltonian (and Lagrangian) contains pair creation terms $\Psi^\dagger \partial_x \Psi^\dagger$ (and the corresponding pair annihilation). In this case in order to write the action as a quadratic form you must first pass to so called Nambu spinor:
$$
\Phi = \left ( \begin{array}{cc} \Psi \\ \Psi^\dagger \end{array} \right ),
$$
taking care of anticommutation relations. 
