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So according to me in this situation there are two forces acting on A at the moment, one is the reactive force of 70 N by newton's third law and the other is the force of 60 N exerted by B. Now don't you think the tension should be the sum of the two pulling forces experienced by A (i.e. 70+60=130 N)...Please tell me where my thinking process is going wrong.

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    $\begingroup$ Does this answer your question? Tension of rope. Different Answers? $\endgroup$
    – James
    Mar 18, 2020 at 18:48
  • $\begingroup$ @James not exactly $\endgroup$ Mar 18, 2020 at 18:51
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    $\begingroup$ You've now asked 5 questions on this topic, and aren't happy with the answers. That's fair enough, but I strongly suggest that you do some relevant experiments. Theory is important, but the foundation of physics is empirical evidence from observation & experiment. So get yourself a couple of spring balances, some string, some weights, and some pulleys (or smooth hooks to pass the string over), and do some experiments. $\endgroup$
    – PM 2Ring
    Mar 19, 2020 at 12:22
  • $\begingroup$ @PM2Ring Well why do you sound so rude...if you don't wanna answer then it's your wish ...no one is forcing you...but sorry i can't relax unless and until i get my concepts clear..thank you $\endgroup$ Mar 19, 2020 at 14:32
  • $\begingroup$ Sorry, CuriousMind, I didn't mean to sound rude. I even said that it's fair enough that you aren't happy with the answers you've been given so far. But I think it will be helpful for you to get some literal hands-on experience with this stuff by doing these experiments. It certainly helped me when I was learning this stuff. $\endgroup$
    – PM 2Ring
    Mar 19, 2020 at 15:10

1 Answer 1

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Please tell me where my thinking process is going wrong.

Your thinking is going wrong because it violates Newton’s 3rd law. If A is applying a force of 70 N on the rope then by Newton’s 3rd law the rope is applying a force of -70 N on A. That is it. Any other value violates Newton’s 3rd law.

The force exerted by B acts on the rope, not on A.

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  • $\begingroup$ But the rope is connecting A and B, if B is pulling A with 60 N then this force must be transfered to A as tension $\endgroup$ Mar 18, 2020 at 19:13
  • $\begingroup$ That is not necessary, and since it would violate Newton’s laws it doesn’t happen. Instead there is a 10 N net force on the rope so it accelerates. $\endgroup$
    – Dale
    Mar 18, 2020 at 19:18
  • $\begingroup$ Hence what will be the tension of the rope in my case? $\endgroup$ Mar 18, 2020 at 19:20
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    $\begingroup$ @Dale: See my discussion with OP at his other question. physics.stackexchange.com/questions/536791/… $\endgroup$
    – James
    Mar 18, 2020 at 19:33
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    $\begingroup$ okay thank you for your time $\endgroup$ Mar 18, 2020 at 19:38

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