1
$\begingroup$

I have several questions:

1) First, In the susceptibility tensor, when it's diagonalized, i don't understand the physical significance when the off diagonal terms are zero.

$$P_x=\epsilon_0\chi_{11}E_x, P_y=\epsilon_0\chi_{22}E_y, P_z=\epsilon_0\chi_{33}E_z$$

2) As i understand D has a different direction from E because the components of E are multiplied by different refractive indices, so to find out the eigenvectors of D we use basis vectors, two of which lie in the phase plane and the third is perpendicular to it. Is this basis same as that in the first question or does it depend on K?

$$[A_\vec u]=P_\perp^\vec u[\eta]=\begin{bmatrix} 1&&0&&0\\0&&1&&0\\0&&0&&0\end{bmatrix}\begin{bmatrix}\eta_{11}&&\eta_{12}&&\eta_{13}\\\eta_{12}&&\eta_{22}&&\eta_{23}\\\eta_{13}&&\eta_{23}&&\eta_{33}\end{bmatrix}$$

$\endgroup$
1
  • $\begingroup$ Hi and welcome to Physics.SE! Your question would sensibly improve if you could typeset your equations with Mathjax though. $\endgroup$
    – lr1985
    Mar 14, 2020 at 18:09

1 Answer 1

0
$\begingroup$

The physical significance of the off-diagonal elements being zero is that your coordinate system's 3 basis vectors are aligned with the principle axes of the medium.

In the second case, you appear to be using a coordinate system in which $\hat z$ is aligned with $\vec k$ of the propagating wave. If those 2 coordinate systems are different, then ${\bf{\chi}}$ need not be diagonal in the latter.

$\endgroup$
2
  • $\begingroup$ I'm new to tensors, so from what i understand, 𝜒11 has different nature than 𝜒21 for example. What does it mean when this component vanish after aligning the basis with the principle axes? $\endgroup$
    – NAD
    Mar 15, 2020 at 8:39
  • $\begingroup$ @Ne123 The vanishing of $\chi_{21}$ means that the x and y axes are aligned w/ 2 principle axes of the medium. They are one in the same. If $\chi_{11}=\chi_{22}=1$ and $\chi_{21}=\chi_{12} = 1/\sqrt 2$, and $\chi_{zz}$ is the only nonzero "z", then the coordinate axes are rotated 45 degrees relative to the principle axes. $\endgroup$
    – JEB
    Mar 16, 2020 at 3:19

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.