I am studying surface plasmons on a nanosphere using classical electrodynamics but I was wondering if surface plasmons were or not eigenstates of the nanoparticle Hamiltonian. I think they are not because you really have to add some boundary conditions on the external field to compute them. Is this true? Can you provide me a detailed explanation?
Thank you in advance EDIT What I meant is that the Hamiltonian: \begin{equation} H=\sum_{i}\frac{p^{2}_{i}}{m_{i}}+\frac{1}{2}\sum_{i,j}\frac{1}{\left|r_{ij}\right|}-\sum_{\gamma,i}\frac{1}{R_{\gamma i}} \end{equation} where $\gamma$ runs over the nuclei and $i,j$ over the electrons won't be enough because:
There is no reference to the surface and the surface plasmon frequency depends on the external zone;
There is no reference to the fields produced by the moving charges (retardation effects); Plus I'm not really sure how one would ensure the boundary conditions on the surface in the solution of quantum mechanical equations