What would be the energy requirements for non FTL warp drive? I have a question about Alcubierre Drive, or other Warp Drive concepts. 
I have read a lot about FTL warp drive and the massive energy requirements to perform a jump, varying from bigger than the observable universe, to the size of Jupiter. 
Unfortunately, nowhere I could find the formula for the aforementioned calculation. 
Assuming gravity/space manipulation is possible and achievable, I would like to know what would be the approximate energy requirements for a non-FTL warp drive. What would be a rough approximation for the required energy to lift 1 kilogram 1 meter above the ground in 1 second, though gravity/space manipulation? Or at least how different, if so, is the result compared to classical means? 
From my understanding, a non-FTL gravity manipulation would still be extremely useful in transportation and space travel.
 A: You can check out nasa research on that. They're focusing on micro warp effects. 
ntrs.nasa.gov/archive/nasa/casi.ntrs.nasa.gov/20110015936.pdf
Even for FTL the energy requirements are extremely low. That it at first of course, not so good, because the energy conditions needed are in the negative. But with the right distribution and some sofistication one coud get even the absolute value of required energy drop down to a quite practical value.  Nonetheless one still needs negative energy which is a bit of a problem no matter how little the amount you need. 
the answers probably lie in the nature of the quantum vacuum. Casimir effect is something that could be considered something producing  energy. But not necceserely in general relativistic sense. 
GR is not a quantum theory anyway, so althaugh it has many exelent predictions, it is fundamentally quite flawed. So I wouldnt give too much attention to its predictions on this kind of stuff. Rather, a quantum source of gravity needs to be understood in order to have the ability to manipulate spacetime in such subtle ways. 
