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In quantization, we frequently run into ordering ambiguities. In general, this means that there can be inequivalent quantum theories corresponding to the same classical theory.

Has there ever been an experiment that favored one choice of ordering to another?

Below is a more detailed description of the same question.

For example, one of the terms in the Hamiltonian of the harmonic oscillator $$ v = q^2 $$ can be quantized either as $$ V = Q^2 = \frac{1}{2} (A + A^{\dagger})^2 = \frac{1}{2} \left( A^2 + A A^{\dagger} + A^{\dagger} A + A^{\dagger 2} \right), $$ or as $$ V_0 = :V: = \frac{1}{2} :(A + A^{\dagger})^2: = \frac{1}{2} \left( A^2 + 2 A^{\dagger} A + A^{\dagger 2} \right) = Q^2 - \frac{1}{2}. $$ The first choice of ordering is rather arbitrary and comes from naively plugging in the expression for $Q$ into the classical formula $v = q^2$ without noticing the ordering ambiguity at all. The second term is obtained through normal ordering, which is arguably the correct physical choice of ordering.

This ordering ambiguity is benign because it only contributes to a constant shift in energy levels, which is unobservable, because experiments only measure differences in energy of two different levels.

However, consider the quartic term $$ u = q^4. $$

This can be quantized as $$ U = Q^4, $$ or as $$ U_0 = :U: = Q^4 - \frac{3}{2} Q^2 + \frac{1}{2}. $$

Let's assume that the latter is the correct physical choice. The constant shift of $1/2$ is again unphysical, but the $-3Q^2/2$ term modifies the Hamiltonian and its energy levels. It is in principle observable, provided that the constant in front of the $Q^2$ term is fixed by some fundamental principle (otherwise, this term will get re-absorbed into the empirical value for that constant).

My question is – is there any known experiment where the ordering ambiguity is experimentally shown to be resolved one way or another?

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  • $\begingroup$ You are basically asking for realistic systems described by different quantum hamiltonians, which, nevertheless, share a common classical limit. A related question is here. But there is no such thing as "resolution" of the ambiguity : nature does not choose orderings. I assume you have boned up on the classic Quantization is a mystery. $\endgroup$ Commented Mar 3, 2020 at 14:03
  • $\begingroup$ @CosmasZachos I understand that nature is quantum and quantization is a heuristic procedure. But if we have two theories with distinct predictions, both obtained by heuristic procedures, in hopes to describe the same quantum phenomenon, experiment should decide which one is right and which is wrong, don't you agree? I'm looking for examples of this situation. $\endgroup$ Commented Mar 3, 2020 at 14:09
  • $\begingroup$ Examples of the different spectra of different hamiltonians? You could cook one up with number operators of an oscillator. $\endgroup$ Commented Mar 3, 2020 at 14:14
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    $\begingroup$ +1 for the question. As far as I am concerned there is ordering ambiguity in the hydrogen atom Hamiltonian: The quantization of the kinetic energy term ought to be rotational invariant around the origin (i.e. the nucleus), but translation invariance is no longer well motivated: this leaves possibilities for quantizations of the form $\mathbf{p}^2 \rightarrow \frac{1}{f(|\mathbf{x}|)}\nabla\cdot (f(|\mathbf{x}|) \nabla ...)$ with $f$ arbitrary. I'm wondering whether the Laplace-Runge-Lenz symmetry (SO(4) symmetry instead of SO(3)) might fix $f=1$. How does Pauli '24 deal with the issue? $\endgroup$
    – 5th decile
    Commented Jul 7, 2021 at 0:01
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    $\begingroup$ Sorry, it's Pauli '26: arxiv.org/pdf/quant-ph/0212010.pdf $\endgroup$
    – 5th decile
    Commented Jul 7, 2021 at 0:08

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