1.) When going through a cycle of a process (A-->B-->A), is the change in the entropy of the system always equal to 0?
Yes. Entropy is a state property. For any cycle that returns the system to its original state, all state properties such as entropy, internal energy, enthalpy, etc. of the system return to their original values.
Does the reversibility of the process change anything (done reversibly
vs irreversibly)?
Yes. For a reversible cycle (cycle consisting of all reversible processes) the change in entropy of both the system and the surroundings is zero. For an irreversible cycle (cycle consisting of at least one irreversible process), the change in entropy of the system is zero, but the change in entropy of the surroundings is greater than zero.
For a reversible process, the increase/decrease in entropy of the system equals the decrease/increase in entropy of the surroundings, so that the change in entropy of the combination of the system and surroundings is zero. An example is a reversible isothermal (constant temperature) expansion of an ideal gas. During the process the entropy of the gas increases by $+\frac{Q}{T}$ where $Q$ is the heat transferred to the gas from the surroundings and $T$ is the temperature of the gas. For the process to be reversible the temperature of the gas has to be in equilibrium with the temperature of the surroundings (equal temperatures). The change in entropy of the surroundings is therefore $-\frac{Q}{T}$. The total or combination entropy change (system + surroundings) is then zero.
2.) When going through a cycle of a process (A-->B-->A), is the change in the entropy of the surroundings always equal to 0? Again, does reversibility have any effect on this.
As indicated in the answer to (1) for a complete cycle the change in entropy of the surroundings is zero only if the system cycle is reversible. It is greater than zero if the system cycle is irreversible.
Hope this helps.