Experiments so far have pinned down the two mass differences of the three neutrino masses. The lowest one, $m_1$, may conceivably be zero, even though in physics massless states need some type of theoretical "protection" (gauge invariance, etc...), which the lightest species could not plausibly have, its other two brothers lacking it! Implausible is not impossible.
Now, if it were the case that $m_1=0$, you could, indeed, get by without a right-chiral neutrino.
But, even if you had one such, could you tell? No. A strictly
"academic" issue, then: in the absence of a mass term, it would never couple to its left-chiral (active) mate and thence to our entire weakly interacting world, our only handle in detecting neutrinos directly; it would be perfectly sterile, so it would be really, truly invisible.
Of course, such extra particles would have gravitational interactions, and dodgy cosmological arguments could account for them, but how do you propose to contrast them to "conventional" dark matter?
Lastly, this extraneous sterile species, cut off from our WI world by its lack of a Dirac mass coupling it to the left-chiral active species, could still have a Majorana mass term coupling it to itself. But this would also be undetectable, except possibly through cosmological means (Hah!). It would be the ultimate invisible particle. An invisible massive sterile neutrino alongside a massless active one! Calling it "neutrino" would be a stretch, then.
The other two neutrino mass eigenstates could violate lepton number (via extra Majorana masses) or not, completely imperviously to it. It is really cut off from their world, and cannot affect it in any way.
(Our entire discussion above avoided the "convenient fakes", the flavor states, and the corresponding PMNS mixings defining them.)