A question about the vertical part of the beam 
I am solving beam type of problems finding reactions, moments...my question is how do I represent the F2 force that is acting on the vertical part of the beam (on the stick).
Usually there is only a beam on supports, forces in the x and y direction a moment, maybe sometimes an angled force or distributed load, this is the first time I see this kind of problem.
Does the F2 on the stick create a counter clockwise moment or is it just a force acting in the x direction, I need to know so I know in which of the equilibrium equations I put it.
 A: Treat it the usual way. Slice the beam and find the force/moment balance. 
For example:

$$\begin{aligned}
  N - F_2 & = 0 \\
  S + B_y & = 0 \\
  M + x B_y + a F_2 & - 0 
\end{aligned} $$
Then use the $N(x)$, $S(x)$ and $M(x)$ as needed.
A: 
Does the F2 on the stick create a counter clockwise moment or is it
  just a force acting in the x direction, I need to know so I know in
  which of the equilibrium equations I put it.

Yes, it creates a counter clockwise moment on the beam and it is also a force in the x direction. It's not clear from the drawing what is going on at the left side of the beam, but it looks like the application of a force-couple (pure moment).
In any event, the fact that there is a vertical extension of the beam and a horizontal force on it, does not complicate the problem. Just treat it as another force that contributes a moment. 
The problem is actually quite simple, mainly because roller supports cannot support horizontal loads. Consequently, the horizontal reaction at roller B has to be zero. That gives you the horizontal reaction at the pin A. From there, simply set the sum of the moments about A or B equal to zero (not forgetting the moment contribution of $F_2$) to get the vertical reaction at A or B. Then take the sum of the vertical reactions and $F_1$ to get the vertical reaction at the other support.
From here you should be able to proceed independently.
Hope this helps.
