# Why doesn't the phonon theory reproduce a Debye-like curve for $C_V$ vs. $T$?

• Debye's theory is a model of specific heat in which a high-frequency cut-off $$\omega_D$$ is put in by hand. The resulting curve of $$C_V$$ versus temperature $$T$$ grows as $$T^3$$ at low $$T$$ and saturates to a constant value at high $$T$$. The ad hoc parameter $$\omega_D$$ is then fitted experimentally.

• The phonon theory also enables us to calculate the contribution of specific heat coming from phonons. It uses the dispersion relation $$\omega=c_sk$$. But that only gives rise to the $$T^3$$ behaviour which is only the low-temperature behaviour. See Ashcroft & Mermin, page 457 for a derivation.

Why does the phonon theory of solids fail to reproduce a Debye-like curve? In case I am ill-informed and it can reproduce a Debye-like curve, please suggest me a reference (preferably a book/lecture note not some research article).

• I had a similar question a few years ago. This might help: physics.stackexchange.com/questions/396479/… Commented Jan 17, 2020 at 15:39
• But I would still recomend reading Ashcroft & Mermin! Other references might be Kittel 'introduction to solid state physics' and a more undergrad level book 'solid state basics' of Steven H. Simon Commented Jan 17, 2020 at 15:41
• I'm actually not sure where you're getting this. In Chapter 23 ("Quantum Theory of the Harmonic Crystal") in my copy of Ashcroft & Mermin, they talk about the general (non-linear) dispersion relations for the normal vibrational modes of a solid. They write down the expression for the heat capacity in terms of the dispersion, and they show that in the high-$T$ limit, this give the law of Dulong and Petit (because the phonon dispersion has a natural cutoff frequency already!); see pages 454-455 ("High-temperature specific heat"). Commented Jan 17, 2020 at 21:45
• @march I know. At page 455, equation 23.14 they did not show that at high T, $C_V$ goes to a constant. The question is how can that be shown. Commented Jan 18, 2020 at 12:06
• @mithusengupta123 Maybe I'm missing something, but I'm pretty sure that the expansion on the top of page 455 does show that the law of Dulong and Petit holds in the limit as $T\to\infty$, because the leading term is of order $k_{\textrm{B}}T$ (leading to D&P), and the rest of the terms decay with increasing temperature. Combined with the fact that there is a natural cut-off frequency for real solids---which renders the integrals over $\omega$ finite---these two facts show that the heat capacity is finite and that D&P occurs in the high-$T$ limit. Commented Jan 21, 2020 at 17:54

At the top of page 455 in Ashcroft and Mermin, they note that one can expand the Bose-Einstein distribution in powers of $$1/T$$ to get the high-temperature expansion. The first term yields the Law of Dulong and Petit, and the rest of the terms decay as a function of $$T$$. Due to the natural high-frequency cut-off caused by the finite distance between atoms, the integrals in each of these terms is also finite. These two facts render the heat capacity finite at high temperatures and that the heat capacity matches the Law of Dulong and Petit as $$T\to\infty$$. For a specific case, consider the following.

1D harmonic model

To the extent that we can treat the vibrations of the lattice as harmonic (i.e. no non-linear oscillator terms), the phonon theory for a 1D solid yields a Debye-like curve.

Dispersion relation and density of states

The dispersion relation for a 1D chain of atoms of mass $$m$$ separated by a distance $$a$$ and connected by springs of spring-constant $$c$$ is $$\omega = 2\sqrt{\frac{c}{m}}\left|\sin\left(\frac{k_xa}{2}\right)\right|,~~~~~~~\mbox{where}~~~~~~-\frac{\pi}{a}\leq k_x\leq \frac{\pi}{a}.$$ Accordingly, the (1D) density of states is given by $$D(\omega) = \frac{L}{\pi}\frac{1}{d\omega/dk},$$ where $$L=Na$$ is the total length of the solid, and $$N$$ is the number of atoms (also the number of primitive unit cells, since there is one atom per unit cell). Using the dispersion relation above, this becomes$$D(\omega)= \frac{N}{\omega_{\textrm{max}}}\frac{2}{\pi} \begin{cases} \frac{1}{\sqrt{1-(\omega/\omega_{\textrm{max}})^2}} & \omega \leq \omega_{\textrm{max}} \\ 0 & \textrm{otherwise} \end{cases},$$ where $$\omega_{\textrm{max}}=2\sqrt{c/m}$$. Importantly, the cutoff frequency $$\omega_{\textrm{max}}$$ is built in automatically: the maximum frequency (minimum wavelength) emerges due to the finite spacing between atoms.

Integral expression for the internal energy

Upon converting the integral over $$k$$ to one over $$\omega$$, the internal energy becomes $$U = \int_0^{\infty}d\omega~D(\omega)\frac{\hbar\omega}{e^{\hbar\omega/k_{\textrm{B}}T}-1} = \int_0^{\omega_{\textrm{max}}}d\omega~\frac{N}{\omega_{\textrm{max}}}\frac{2}{\pi}\frac{1}{\sqrt{1-(\omega/\omega_{\textrm{max}})^2}}\frac{\hbar\omega}{e^{\hbar\omega/k_{\textrm{B}}T}-1}.$$ Upon changing variables to $$x=\omega/\omega_{\textrm{max}}$$, this becomes $$U= \frac{2N}{\pi}\hbar\omega_{\textrm{max}}\int_0^{1}dx~\frac{1}{\sqrt{1-x^2}}\frac{x}{e^{x(\hbar\omega_{\textrm{max}}/k_{\textrm{B}}T)}-1}.$$

Heat capacity

The heat capacity is given by $$\frac{\partial U}{\partial T} = k_{\textrm{B}}\frac{2N}{\pi}\left(\frac{\hbar\omega_{\textrm{max}}}{k_{\textrm{B}}T}\right)^2\int_0^{1}dx~\frac{1}{\sqrt{1-x^2}}\frac{x^2e^{x(\hbar\omega_{\textrm{max}}/k_{\textrm{B}}T)}}{\left(e^{x(\hbar\omega_{\textrm{max}}/k_{\textrm{B}}T)}-1\right)^2}.$$ This integral is finite for all positive values of $$T$$. Below, I've plotted this heat capacity (solid) along with the corresponding Debye interpolation (dashed) as a function of $$T$$. We can see that both follow the Law of Dulong and Petit at high temperatures, that they are linear at low temperatures (and agree), and that the phonon model yields a higher heat capacity at intermediate temperatures due to the rounding-off of the dispersion relation (i.e. more modes at lower frequencies means the higher frequency modes "turn on" at lower temperatures than in the Debye model with the linear dispersion relation. (Note that in order to compare the two, I matched the long-wavelength speed of sound of the two models, which results in $$\omega_{\textrm{D}} = \frac{\pi}{2}\omega_{\textrm{max}}$$.)