# Displacement related question

So you have two tracks of different inclines meeting at a point. Two stones are released from this point each one along the direction of one incline, from rest. Which stone reaches the ground faster? The one on the steeper incline? I don't understand why. By the kinematic equations of motion displacement in the y direction is equal to -gt^2 for both the motions, and since they are released from the same height, they should reach at the same time. I feel like i'm missing something very important...

• I have used the fact that the s=ut+1/2(at^2) is a vector equation with three independent equations satisfying the x, y and z directions respectively. I also wish to know how we can account for the horizontal velocity of the ball when it has no acceleration in the horizontal direction and starts with initial velocity 0? – kimi Jan 14 at 16:31

You are forgetting the fact that here normal reaction acting from the track changes the direction of motion the object and only a smaller component of acceleration due to gravity is acting along the direction of motion ($$\leq g$$).