Is it wrong to describe the angular momentum of a photon as its "spin?" In my physics classes, we described spin as a quantum property of electrons---that is, their angular momentum. Photons also have angular momentum, and when the angular momentum of photons is aligned, we say that we have polarized light. But I have never seen the angular momentum of photons described as photonic spin or a photon's spin. Why is that? Is it wrong to describe the photon's angular momentum as its spin?
 A: No it is not wrong. The intrinsic angular momentum of a photon is spin. But note that photons can also have orbital angular momentum (and so can electrons). 
Orbital angular momentum is defined as
$$
\hat{L} = \hat{\bf x} \times \hat{\bf p}
$$
where $\hat{\bf x}$ is the position operator and $\hat{\bf p}$ is the linear momentum operator. Just as in classical mechanics, the amount of such angular momentum which any given entity has depends on the choice of the origin of coordinates, as well as on the entity's own motion. It is a quantity useful to physics because it is conserved in isolated systems in the absence of spin-orbit interaction (also true in classical mechanics). Finally, the total angular momentum
$$
\hat{\bf J} \equiv \hat{\bf L} + \hat{\bf S}
$$
is conserved in isolated systems (and this also holds in classical mechanics). Spin-orbit interaction can move angular momentum between the two forms, without changing $\bf J$.
One way to define spin is to say that it is that part of the total angular momentum which is not orbital angular momentum. Another way to define spin is simply to assert at the outset that one is dealing with a certain kind of quantum field, described by scalar quantities (spin zero) or the simplest spinor quantities (spin half) or vector quantities (spin one) etc. In either case the conservation of total angular momentum, as opposed to just orbital angular momentum, is connected to symmetries under rotation. But that requires a more advanced mathematical level than I think this question and answer is looking for. 
P.S. The word 'orbital' in 'orbital angular momentum' does not necessarily mean any particle need be in an orbit about something. A particle moving in a straight line can and does have orbital angular momentum about any point not on that line. I mention this as an antidote to some nonsense statements that I saw in other answers. 
P.P.S. It is the photon's orbital angular momentum that ensures conservation of angular momentum in atomic transitions when the atom's angular momentum changes by more than one through the emission of a single photon; such transitions are not dipole transitions (they are quadrupole or octapole etc.)
A: Spin is the (usually) finite-dimensional and unitary representation of the Lorentz group in which the state transforms (unless you want to study continuous spin) and for massive particles the "little group" approach well expounded be Weinberg leads to irreducible representations labelled by $su(2)$ variables $j$ and $m_{j}$.
For massless particles the analyses is slightly different as the little group is $\mathcal{E}(2)$, the Euclidean group in 2 dimensions. This admits continuous spin representations and demanding that this is avoided leaves only trivial, one-dimensional representations labelled by the helicity, $h$. (In a theory with parity, you get $\pm h$ states connected).
Another way of saying it is that spin and helicity are different for massive particles (helicity being the projection of spin along the 3-direction of movement) whereas for massless particles, travelling at $c$, the spin and helicity coincide.
In my opinion it is perfectly fine to say a photon has spin 1, as we know that for the massless particle spin is helicity. The only danger is that a massive spin 1 triplet has a longitudinal (m=0) state that does not exist for the massless photon. This is the difference between massive and massless. See also the Pauli-Lubanski vector. Massless objects have velocity four vectors that are null and as such travel at the speed of light. 
A: Light can have orbital and intrinsic angular momentum. It is the latter that is related to polarisation and spin. The problem is that there is no gauge invariant expression for it. In the standard, gauge theory of light all angular momentum is described as orbital momentum!
This paradox is at the root of your question. Light has spin but the present theory cannot not explicitly describe it. Either you have gauge invariance and no spin, or spin and no gauge invariance. Present physics takes the first option. I published a paper showing that you can also take the second. See https://arxiv.org/abs/physics/0106078. 
