# How to setup a voltage divider to provide a reduced voltage for a lamp

I am learning about voltage dividers.

In simple words, a voltage divider is a specific circuit setup where we connect multiple passive elements in series, in order to divide the main voltage into small voltage drops.

The voltage drop for each element is proportional to its resistance.

If I have a lamp that needs 6 V (and not more), but I have a 12 V supply, how is the voltage divider really created?

I could replace the lamp with a resistance of let’s say 3 ohms, and then say that I need another resistance connected with the lamp.

But this question arises:

• Can a lamp (I intend the common Joule effect based lamp, not any other type of lamp) actually be “just” considered a resistance? The resistance will change with temperature and temperature will definitely change.

I guess the answer is no but I don’t know the exact reason. Also, being that the case... how would the circuit be in this case? I guess something like this makes most sense: But again that changes the circuit and I don’t know if that setup will actually deliver 6 V to the lamp. In case this setup is wrong, how would I achieve the expected solution? To deliver only 6 V to that element. What are the real magnitudes that need to be known in order to make this happen in reality?