# Symmetry on Bohr's Hydrogen Atom

I was studying the applications of the Schröedinger wave function in the Bohr's atom.

For what I understood, the $$\psi$$ should only depend on r and not on $$\theta$$ and $$\phi$$. Does that mean that $$\psi(r, \theta, \phi)=R(r)$$?

In general the wavefunction depends on all the coordinates. However, there are special states called $$s$$ states, without any angular momentum, where it depends only on $$r$$.
• And there is a symmetry in the $1/r^2$ potential that makes that other values of the angular momentum quantum number have the same energy. – Pieter Nov 29 '19 at 0:25